[4.19,221/422] blok, bfq: do not plug I/O if all queues are weight-raised

Message ID 20191119051412.950455318@linuxfoundation.org
State New
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  • Untitled series #25073
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Commit Message

Greg KH Nov. 19, 2019, 5:16 a.m.
From: Paolo Valente <paolo.valente@linaro.org>

[ Upstream commit c8765de0adfcaaf4ffb2d951e07444f00ffa9453 ]

To reduce latency for interactive and soft real-time applications, bfq
privileges the bfq_queues containing the I/O of these
applications. These privileged queues, referred-to as weight-raised
queues, get a much higher share of the device throughput
w.r.t. non-privileged queues. To preserve this higher share, the I/O
of any non-weight-raised queue must be plugged whenever a sync
weight-raised queue, while being served, remains temporarily empty. To
attain this goal, bfq simply plugs any I/O (from any queue), if a sync
weight-raised queue remains empty while in service.

Unfortunately, this plugging typically lowers throughput with random
I/O, on devices with internal queueing (because it reduces the filling
level of the internal queues of the device).

This commit addresses this issue by restricting the cases where
plugging is performed: if a sync weight-raised queue remains empty
while in service, then I/O plugging is performed only if some of the
active bfq_queues are *not* weight-raised (which is actually the only
circumstance where plugging is needed to preserve the higher share of
the throughput of weight-raised queues). This restriction proved able
to boost throughput in really many use cases needing only maximum

Signed-off-by: Paolo Valente <paolo.valente@linaro.org>

Signed-off-by: Jens Axboe <axboe@kernel.dk>

Signed-off-by: Sasha Levin <sashal@kernel.org>

 block/bfq-iosched.c | 10 ++++++++--
 1 file changed, 8 insertions(+), 2 deletions(-)



diff --git a/block/bfq-iosched.c b/block/bfq-iosched.c
index 35ddaa820737c..66b1ebc21ce4f 100644
--- a/block/bfq-iosched.c
+++ b/block/bfq-iosched.c
@@ -3593,7 +3593,12 @@  static bool bfq_better_to_idle(struct bfq_queue *bfqq)
 	 * whether bfqq is being weight-raised, because
 	 * bfq_symmetric_scenario() does not take into account also
 	 * weight-raised queues (see comments on
-	 * bfq_weights_tree_add()).
+	 * bfq_weights_tree_add()). In particular, if bfqq is being
+	 * weight-raised, it is important to idle only if there are
+	 * other, non-weight-raised queues that may steal throughput
+	 * to bfqq. Actually, we should be even more precise, and
+	 * differentiate between interactive weight raising and
+	 * soft real-time weight raising.
 	 * As a side note, it is worth considering that the above
 	 * device-idling countermeasures may however fail in the
@@ -3605,7 +3610,8 @@  static bool bfq_better_to_idle(struct bfq_queue *bfqq)
 	 * to let requests be served in the desired order until all
 	 * the requests already queued in the device have been served.
-	asymmetric_scenario = bfqq->wr_coeff > 1 ||
+	asymmetric_scenario = (bfqq->wr_coeff > 1 &&
+			       bfqd->wr_busy_queues < bfqd->busy_queues) ||