diff mbox series

[PULL,35/54] target/mips: Fix possible MSA int overflow

Message ID 20250306154737.70886-36-philmd@linaro.org
State New
Headers show
Series [PULL,01/54] qemu/compiler: Absorb 'clang-tsa.h' | expand

Commit Message

Philippe Mathieu-Daudé March 6, 2025, 3:47 p.m. UTC 
From: Denis Rastyogin <gerben@altlinux.org>

Fix possible overflow in 1 << (DF_BITS(df) - 2) when DF_BITS(df)
is 64 by using a 64-bit integer for the shift operation.

Found by Linux Verification Center (linuxtesting.org) with SVACE.

Reported-by: Dmitriy Fedin <d.fedin@fobos-nt.ru>
Signed-off-by: Denis Rastyogin <gerben@altlinux.org>
Reviewed-by: Peter Maydell <peter.maydell@linaro.org>
Message-ID: <20250124122707.54264-1-gerben@altlinux.org>
Signed-off-by: Philippe Mathieu-Daudé <philmd@linaro.org>
---
 target/mips/tcg/msa_helper.c | 6 +++---
 1 file changed, 3 insertions(+), 3 deletions(-)
diff mbox series

Patch

diff --git a/target/mips/tcg/msa_helper.c b/target/mips/tcg/msa_helper.c
index ec38d9fde5e..74fb80cc256 100644
--- a/target/mips/tcg/msa_helper.c
+++ b/target/mips/tcg/msa_helper.c
@@ -5577,7 +5577,7 @@  static inline int64_t msa_mulr_q_df(uint32_t df, int64_t arg1, int64_t arg2)
 {
     int64_t q_min = DF_MIN_INT(df);
     int64_t q_max = DF_MAX_INT(df);
-    int64_t r_bit = 1 << (DF_BITS(df) - 2);
+    int64_t r_bit = 1LL << (DF_BITS(df) - 2);
 
     if (arg1 == q_min && arg2 == q_min) {
         return q_max;
@@ -5685,7 +5685,7 @@  static inline int64_t msa_maddr_q_df(uint32_t df, int64_t dest, int64_t arg1,
 
     int64_t q_max = DF_MAX_INT(df);
     int64_t q_min = DF_MIN_INT(df);
-    int64_t r_bit = 1 << (DF_BITS(df) - 2);
+    int64_t r_bit = 1LL << (DF_BITS(df) - 2);
 
     q_prod = arg1 * arg2;
     q_ret = ((dest << (DF_BITS(df) - 1)) + q_prod + r_bit) >> (DF_BITS(df) - 1);
@@ -5700,7 +5700,7 @@  static inline int64_t msa_msubr_q_df(uint32_t df, int64_t dest, int64_t arg1,
 
     int64_t q_max = DF_MAX_INT(df);
     int64_t q_min = DF_MIN_INT(df);
-    int64_t r_bit = 1 << (DF_BITS(df) - 2);
+    int64_t r_bit = 1LL << (DF_BITS(df) - 2);
 
     q_prod = arg1 * arg2;
     q_ret = ((dest << (DF_BITS(df) - 1)) - q_prod + r_bit) >> (DF_BITS(df) - 1);